Question 1110236
I'm assuming the line segments are of the triangle, not of the arc of the circle.  I am assuming the shaded area is the area outside the triangle.
If one leg is 44 and the hypotenuse  (PR) is 54, then the third leg is (54^2-44^2)^(1/2)=31.305 (I won't round until next step).
Because it is a right triangle, the area is (1/2) b*h, and b and h are the base and altitude or sides
This would give a triangular area of 688.71 (rounding here).
The area of the semicircle is (1/2)*pi*27^2, as radius is 27, or 1145.110
The shaded area or area(s) I am assuming are not filled by the triangle.  Their total area would be 1145.110 minus the area of the triangle or 456.40 sq units.