Question 1110067
<pre>
F(x) = f(x<sup>5</sup>)

Using the chain rule:

F'(x) = f'(x<sup>5</sup>)&#8729;5x<sup>4</sup>

F'(a) = f'(a<sup>5</sup>)&#8729;5a<sup>4</sup>

F'(a) = 8&#8729;5&#8729;10

F'(a) = 400

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G(x) = [f(x)]<sup>5</sup>

Using the chain rule:

G'(x) = 5&#8729;[f(x)]<sup>4</sup>&#8729;f'(x)

G'(a) = 5&#8729;[f(a)]<sup>4</sup>&#8729;f'(a)

G'(a) = 5&#8729;3<sup>4</sup>&#8729;3

G'(a) = 1215

Edwin</pre>