Question 1110198
<br>
This equation is in slope-intercept form, y=ax+b, with a=1 and b = -4:
{{{y = ax+b = (1)x+(-4) = x-4}}}<br>
In this form, the a is the slope and the b is the y-intercept.<br>
The intercept -- or more precisely, the y-intercept, is where the graph crosses the y-axis.  Since everywhere on the y-axis the x value is 0, the y-intercept is the value of the function when x is 0:
{{{y = x-4 = 0-4 = -4}}}
The y-intercept is -4, or (0,-4).<br>
So start your graph by marking the point (0,-4) on your graph.<br>
The slope, a=1, tells you how much the graph rises (positive slope) or falls (negative slope) each time you "take one step forward" -- i.e., move 1 to the right.  So a slope of 1 tells you that each time you move 1 to the right, the graph moves up 1.<br>
So starting at your y-intercept of (0,-4), repeatedly move right 1 and up 1 to plot another point, until you have enough points to make a relatively accurate line.<br>
Or you could just go 5 to the right and up 5 and plot just one more point.<br>
When you have enough points, draw the line containing all the points.  Remember that the line continues infinitely in both directions; it doesn't just contain the points you plotted.