Question 1110002
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(1) At 09:00 car A started its journey and traveled at 70 km/h.

(2) At 10:30 car B started from the same place and traveled steadily on the same road. Car B took 3 1/2 h to catch up with car A. 

(3) At 15:24, car B reached its destination. 

(4) When did car A reach the same destination?
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Catching up moment was at 10:30 + 3 h 30 min = 14:00.

From 9:00 till 14:00 the car A moved 5 hours and covered  5*70 = 350 kilometers.  

From 10:30 till 14:00 car B moved 3.5 hours and covered the same distance.  So, its rate was  {{{350/3.5}}} = 100 km/h.


After catching up moment, car B was on the way from 14:00 till 15:24, i.e 1 hour and 24 minutes = {{{1}}}{{{24/60}}} hours = 1.4 hours.

and covered 100*1.4 = 140 kilometers.


The car A took {{{140/70}}} = 2 hour to cover the same 140 km.  So, car A arrived to the destination point at 14:00 + 2 hours = 16:00.
</pre>

<U>Answer</U>.  The car A reached the same destination point at 16:00.