Question 1109933
{{{x}}}= the width of the frame, in inches
Here is a sketch showing what the picture would look like
{{{drawing(440,340,-2.8,19.2,-4,13,
rectangle(-2,-2,17,12),
rectangle(0,0,15,10),
locate(7,10,15),locate(0.1,5.5,10),
arrow(9,0,9,-2),arrow(9,-2,9,0),
arrow(3,10,3,12),arrow(3,12,3,10),
locate(3.1,11.5,x),locate(9.2,-0.5,x),

arrow(-2,3,0,3),arrow(0,3,-2,3),
arrow(15,9,17,9),arrow(17,9,15,9),
locate(-1.3,3,x),locate(15.7,9,x),
arrow(18,5.5,18,12),arrow(18,4.5,18,-2),
arrow(6.2,-3,-2,-3),arrow(8.8,-3,17,-3),
locate(6.3,-2.6,15+2x),locate(17.1,5.5,10+2x)
)}}} , with lengths (in inches) shown.
 
The perimeter of the rectangle formed by the painting and its frame (in inches) is
{{{(15+2x)+(10+2x)+(15+2x)+(10+2x)=66}}} .
{{{50+8x=66}}}
{{{8x=66-50}}}
{{{8x=16}}}
{{{x=16/2}}}
{{{x=2}}}
The width of the frame is {{{highlight(2inches)}}} .