Question 99502
6x^2 - 28x - 48
First lets factor out 2;
{{{2(3x^2-14x-24)}}}
Now lets factor, lets put aside the 2 for now and then bring it back after we factor the equation;
(3x+4)(x-6)=0
now bring in the 2 and distribute;
2(3x+4)=0
6x+8=0
6x=-8
{{{x=-8/6}}}
2(x-6)=0
2x-12=0
2x=12
x=6
Now we plug each answer we got for x into the original equation and check which one is the correct one;
{{{6(-8/6)-28(-8/6)-48=0}}}
{{{-8+224/6-48=0}}}
{{{-112/6=0}}} no
{{{6(6)^2-28(6)-48=0}}}
6(36)-168-48=0
216-168-48=0
0=0  yes
so the answer;
x=6
:)