Question 1109761
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All three earlier responses from other tutors showed the same setup for the problem.  Just to demonstrate that there are nearly always different ways to solve a problem, here is what I would do with this problem.<br>
The sum of their current ages is 115; 14 years ago that sum was 115-28 = 87.
Back then, Joe was twice as old as Sheila; a bit of arithmetic shows their ages back then were 58 and 29.
So now, 14 years later, Joe is 72 and Sheila is 43.