Question 1109774
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The answer, as the other tutor showed, is -1/4, not 1/4.<br>
If the roots of {{{(x-1)(x-2)=p}}} are equal, then {{{(x-1)(x-2)-p}}} is a perfect square.<br>
{{{(x-1)(x-2)-p = x^2-3x+2-p}}}<br>
If that is to be a perfect square, then it must be equal to {{{(x-3/2)^2 = x^2-3x+9/4}}}.<br>
Therefore, {{{2-p = 9/4}}} --> {{{p = -1/4}}}