Question 1109695
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<pre>
Let  "r"  be the rate of the slower train, in km/h/

Then the rate of the faster train is (r+20) km/h.


The "total distance equation" is


6r + 6*(r+20) = 1692    kilometers


6r + 6r + 120 = 1692

12r = 1692 - 120 = 1572  ====>  r = {{{1572/12}}} = 131.



<U>Answer</U>.  The slower train speed is 131 km/h.  The faster train speed is 131+20 = 151 km/h.
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To see othes similar solved problems, see the introductory lessons on Travel and Distance

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems-for-two-bodies-moving-toward-each-other.lesson>Travel and Distance problems for two bodies moving in opposite directions</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

in this site.