Question 99480
{{{x/((5x + 10))}}} + {{{((x-3))/((x+2))}}} = {{{7/5}}}
:
factor out 5 in the 1st denominator:
{{{x/(5(x + 2))}}} + {{{((x-3))/((x+2))}}} = {{{7/5}}} 
:
Multiply equation by 5(x+2), and eliminate the denominators, leaving us with:
x + 5(x-3) = 7(x+2)
:
x + 5x - 15 = 7x + 14
x + 5x - 7x = 14 + 15
-x = +29
x = -29
:
:
Check solution, substitute -29 for x in the original equation:
{{{(-29)/((5(-29) + 10))}}} + {{{(((-29)-3))/(((-29)+2))}}} = {{{7/5}}}
{{{(-29)/((-145 + 10))}}} + {{{((-32))/((-27))}}} = {{{7/5}}}
{{{(-29)/((-135))}}} + {{{((-32))/((-27))}}} = {{{7/5}}}
Check using decimals
 +.2148  +  1.1852 = 1.4 which is 7/5