Question 99461
x-13/x^2-x-12 + 3x-3/x^2-x-12
Could you tell me if I have this correct I got: 4 / x - 4
Is this correct?
:
Not quite, since you have the same denominators we can write it:
{{{((x-13+3x-3))/((x^2-x-12))}}} = {{{((4x-16))/((x-4)(x+3))}}} = {{{(4(x-4))/((x-4)(x+3))}}} = {{{4/((x+3))}}}
:
Note that the (x-4)'s cancel