Question 99588
{{{x^2 + (x+1)^2 = 85}}}
Make x one of those numbers and the x+1 would be the next consecutive number.

{{{x^2 + x^2 + 2x + 1 = 85}}}

{{{2x^2 + 2x + 1 = 85}}}

{{{2(x^2 + x) = 84}}}

{{{x^2 + x = 42}}} then {{{x^2 + x - 42 = 0}}}
{{{(x + 6)(x - 7) = 0}}} so {{{x = -6}}} and {{{x = 7}}} are solutions. Since a negative squared is positive, you can just use 6 and 7. 
{{{6^2 + 7^2 = 85}}}
{{{36 + 49 = 85}}}