Question 99590
{{{2(x-5)^2=3}}}
I would personally expand the {{{(x-5)^2}}} first.
That gives us:
{{{2(x^2 - 10x + 25) = 3}}}

Then multiply by the 2:
{{{2x^2 - 20x + 50 = 3}}}

Then subtract the 3:
{{{2x^2 - 20x + 47 = 0}}}

You aren't going to like this, but you have to use the quadratic formula for this one.
*[invoke quadratic "x", 2, -20, 47 ]