Question 1109357

if
{{{p(x)=x^2+x+1}}}
{{{q(x)=3x-2}}}

then {{{(p/q)(x)=(x^2+x+1)/(3x-2)}}} will be:

{{{(p/q)(x)=(x^2+x+1)/(3x-2)}}}

domain of {{{(p/q)(x)=(x^2+x+1)/(3x-2)}}} will be all values of {{{x}}} except the value that makes denominator {{{(3x-2)=0}}} 

and, it will be {{{3x-2=0}}} ->{{{3x=2}}}  ->{{{x=2/3}}} 

so, domain is: { {{{x}}} element {{{R }}}: {{{x<>2/3}}} }