Question 1109379
You are correct.
 
UNREQUESTED NOTES:
You are probably starting to learn about sequences,
and will probably face puzzling problems like that right now.
After the puzzling start, problems become similar to one another,
comfortably boring, and there is less guessing required. 
You may be even told to look at differences between consecutive terms
(in this case, 4, 6, 8),
and then second differences (6-8=2, 8-6=2).
If first differences are all the same number {{{d}}} ,
you have what they call an arithmetic sequence,
and terms would have a formula like
{{{A(n)=a+dn}}} or {{{A(n)=A(1)+(n-1)d}}}
If second differences are all the same number,
there will be an {{{n^2}}} term in the formula for {{{A(n)}}} .
In your case, {{{A(n)=n^2+n=n(n+1)}}} .