Question 1109371
(3x+4yi)(3+5i) = 6+2i
{{{ 9x+15xi+12yi+20yi^2 = 6+2i}}}
{{{ 9x+15xi+12yi -20y = 6+2i}}}
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Grouping real and imaginary parts:

{{{ (9x-20y) + (15x+12y)i = 6+2i }}}
Set LHS real = RHS real and  LHS imaginary = RHS imaginary:
{{{ 9x - 20y = 6 }}}
{{{ 15x +12y = 2 }}}

You now have two equations with two unknowns, and you should be able to
solve to get:
    x = 14/51,   y=-3/17
or approximately:
    x=0.27451,  y=-0.17647