Question 1109256
If {{{x^2+bx-20}}} is factorable, {{{x^2+bx-20=(x+p)(x-q)=x^2+(p-q)x-pq}}} ,
Where {{{p}}} and {{{q}}} are positive integers.
So, {{{pq=20}}} and {{{b=p-q}}} .
As {{{p}}} and {{{q}}} must be positive integer factors of {{{20}}} ,
The maximum value of {{{b=p-q}}} is {{{20-1=highlight(19)}}}