Question 1109202
<br>
{{{x^2+6x-16 = 0}}}<br>
a=1; b=6, c=-16<br>
{{{b^2-4ac = 6^2-4(1)(-16) = 36+64 = 100}}}<br>
The discriminant is positive; the equation has two unequal real solutions.<br>
(Note, furthermore, that since the discriminant is a perfect square, the real solutions are rational numbers.)