Question 99558




First convert the standard equation {{{3x-2y=8}}} into slope intercept form


*[invoke converting_linear_equations "standard_to_slope-intercept", 3, -2, 8, 2, 1]




Now let's find the equation of the line that is perpendicular to {{{y=(3/2)x-4}}} which goes through (-6,5)


*[invoke equation_parallel_or_perpendicular "perpendicular", "3/2", "-4", -6,5]