Question 1109142
{{{f(a)=(17)/(2a^3) + (1)/(8a^2) - 119}}}
{{{f(a)=(17/2)a^-3 + (1/8)a^-2 - 119}}}
f'(a)= {{{(-51/2)a^-4 + (-1/4)a^-3}}}