Question 1108899
sample size is 20.


z-score for 95% confidence interval would be plus or minus 1.959963986.


t-score for 95% confidence interval would be plus or minus 2.093024022, using 19 degrees of freedom (sample size of 20 - 1 = 19 degrees of freedom).


if you mis-understood the z-score to be the t-score, the resulting confidence interval would be too narrow.


if the z-score was interpreted as the t-score, then a t-score of plus or minus 1.959963986 with 19 degrees of freedom would generate a confidence level of .9351665248 = 93.5%.


that would be less than the desired 95%.