Question 1109123
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<pre>
csc(t+40°) = sec(t-20°)     <=== ===>

sin(t+40°) = cos(t-20°)     <=== ===>

(t+40°) + (t-20°) = 90°


2t + 20° = 90°  ====>  2t = 90° - 20° = 70°  ====>


There are TWO solutions in the interval  0 <= t < 360°:


    1)  t = {{{70^o/2}}} = 35°,     and

    2)  t = {{{70^o/2}}} + 180° = 215°.
</pre>


{{{graph( 330, 330, -20, 400, -5.5, 5.5,
          1/sin((x+40)*(6.28/360)), 1/cos((x-20)*(6.28/360))
)}}}


Plots y = 1/csc(t+40)  (red)  and  y = 1/sce(t-20) (green)  


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;(horizontal axis in degrees)