Question 1109044
{{{n/(n+2)+(n+2)=28/5}}}


{{{(5(n+2))(n/(n+2)+(n+2))=28(n+2)}}}


{{{5n+5(n+2)^2=28(n+2)}}}


{{{5n+5(n^2+4n+4)=28n+56}}}


{{{5n^2+20n+20=23n+56}}}


{{{5n^2-3n-36=0}}}


{{{(5n+12)(n-3)=0}}}
One good choice is {{{n=3}}} and the fraction was {{{highlight(3/5)}}}.

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You can also check on 5n+12=0, solve for n, and find if this value also works for the original description; according to the original equation.