Question 1108855
Draw the trapezium in system as the line ab=cd ,then line bc=da
    Then since ab=2y,bc=y+3,cd=5x-1,da=2x+4
          Recall, ab=cd
                  bc=da
That is:    2y=5x-1....eqn (i)
            y+3=2x+4...eqn (ii)
         
                  2y-5x=-1...(i)
                  y-2x=1....(ii)
  By substitution method..2y=-1+5x. => y=(-1+5x)/2
      Then substitute the value of y in eqn (ii) 
                 (-1+5x)/2-2x=1. => (-1+5x)-4x=2
                     -1+5x-4x=2
                      -1+x=2
                   X=2+1. => 3
   Use eqn (ii) to find y ..y-2x=1..y=1+2*3 =>7 therefore. X=3. and y=7