Question 1108771
For only one, the probability is 7C1*(0.8)^6*(0.2)^1, The 7C1 are the 7 ways the one parcel may arrive late
That is 7*.8^6*.2=0.3670.

This makes intuitive sense because the expected value is np=1.4, near the 1, so this will be a fairly high probability.