Question 99515
Ok the object is to find two whole numbers. Lets call those numbers x and y.
Now the question states that these two numbers ( x and y) have a product that equals 147. 
lets write that as and equation
{{{(x)(y)=147}}}
We are also told that these numbers ( x and y ) have a quotient of 3
written as an equation we get this:
{{{x/y=3}}}
Ok lets take a look at the first equation:
{{{(x)(y)=147}}}
We can set it in terms of x by dividing both sides by y like this:
{{{(xy)/(y)=147/y}}}
{{{x=147/y}}}
Now we have x equal to 147 divided by y so if we take the second equation
{{{x/y=3}}} 
and replace the x with 147/y we get this:
{{{(147/y)/y=3}}}
now we can solve for y
first multiply both sides by y
{{{(y)((147/y)/y)=3(y)}}}
{{{147/y=3y}}}
next multiply both sides by y again
{{{147=3y^2}}}
now divide both sides by 3
{{{49=y^2}}}
finally solve for y by taking the square root of both sides
{{{sqrt(49)=sqrt(y^2)}}}
{{{7=y}}}
Now that we have found y equals 7 just replace the y in {{{(x)(y)=147}}} with 7
and solve for x
{{{(x)(7)=147}}}
{{{(7x)/7=147/7}}}
{{{x=21}}}
So now we have found two numbers 21 and 7
Their product is 147
{{{(21)(7)=147}}}
and their quotient is 3
{{{21/7=3}}}