Question 1108697
y=-x^2-2x+3
{{{y=-x^2-2x+3}}}


{{{y=-(x^2+2x-3)}}}
{{{y=-(x^2+2x+1-1-3)}}}, completing the square
{{{y=-((x+1)^2+4)}}}
-
{{{highlight(a=-1)}}}
vertex is point (-1,4).


The roots or zeros:
{{{-(x+1)^2+4=0}}}
{{{(x+1)=0+- 2}}}
{{{x=-1-2}}}, and {{{x=-1+2}}}
ZEROS  -3 and +1.


You should be able to do the rest.


{{{graph(300,300,-5,5,-5,5,-x^2-2x+3)}}}