Question 1108548
{{{ ((3ab^2c^3) / (ab)) * (2a^3b^4) }}}

=  {{{  3bc^3 * (2a^3b^4) }}}   <<< performed this part {{{  ((3ab^2c^3) / (ab)) }}}

———————
Details of previous step:    {{{   ((3ab^2c^3) / (ab)) =  3(a/a)*(b^2/b)*c^3 = 3*a^0*b^1*c^3 = 3bc^3 }}}
This step used these properties of exponents  {{{ y^n * y^m = y^(n+m) }}} and {{{ y^n / y^m = y^(n-m) }}}
———————

= {{{  (3*2)*a^3*b^(1+4)*c^3 }}}   <<<  just showing step-by-step
= {{{  6*a^3*b^5*c^3 }}}    <<<  answer
= {{{  6a^3b^5c^3 }}}    <<< by convention, multiplication symbols can be omitted so it can be written this way (you will see this very often)