Question 1108547
{{{ 2y^2(x-1) - 8x(y^2+1) }}} 
= {{{ highlight( 2y^2x) - 2y^2 - highlight( 8y^2x) - 8x }}}  <<< carried out the indicated multiplications; quite often you must do this first
= {{{ -2y^2 - 6xy^2 - 8x }}}     <<< simplified by combining {{{ 2y^2x - 8y^2x }}} (and re-wrote the x first)