Question 1108284
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<pre>
Since f(x) has the roots at x= 0  and  x= 10,


f(x) = k*(x-0)*(x-10) = kx*(x-10)  


at some real "k".



Since f(x) has the minimum -100,

-100 = f(5) = 5k*(5-10) = 5k*(-5) = -25k,


which implies  k = {{{-100/(-25)}}} = 4.



Thus f(x) = 4x*(x-10) = {{{4x^2 - 40x}}}.
</pre>

Solved.