Question 1108173
area of a square is equal to s^2, where s represents the length of a side.


if you let x = the area of the square, then the formula becomes s^2 = x.


if you double the length of the side of the square, then the length of the side of the square becomes 2s.


the area becomes (2s)^2 = 4s^2.


when you double the length of the square, the area is increased by 1875 square inches.


you get 4s^2 = x + 1875


so, you have s^2 = x and 4s^2 = x + 1875.


in the equation 4s^2 = x + 1875, replace s^2 by x, because s^2 = x, to get:


4x = x + 1875.


subtract x from both sides of this equation to get:


3x = 1875.


solve for x to get x = 625.


since x represents the area of the original square, then x = 625 square inches.


the length of the side of that square would be sqrt(625) = 25 inches.


if you double the length of the side of the original square, then the length becomes 50.


the area of that square becomes 50^2 = 2500 square inches.


2500 - 625 = 1875 square inches additional.


your solution is that the length of each side of the original square is 25 inches.