Question 99292
Problem# 39:  
Solve for C: 
{{{(1/2)(c+8) = (1/4)c}}}
:
Get rid of the denominator, multiply equation by 4:
4*{{{(1/2)(c+8)}}} = 4*{{{(1/4)c}}}
:
Cancel out the denominators and you have;
2(c+8) = 1c
2c + 16 = c; multiply what's inside the brackets
2c - c = -16; subtract c and 16 from both sides
c = -16
:
Check solution by substitution in original equation:
{{{(1/2)(-16+8) = (1/4)(-16)}}}
{{{(1/2)(-8) = (1/4)(-16)}}}
-4 = -4
:
:
Problem# 41: Solve for A: 
{{{(1/5)a + 8 = (-3/5)(a-15)}}}
;
Multiply equation by 5 to get rid of the denominators:
5*{{{(1/5)a}}} + 5(8) = 5*{{{(-3/5)(a-15)}}}
:
1a + 40 = -3(a-15)
a + 40 = -3a + 45
a + 3a = 45 - 40
4a = 5
a = 5/4
:
:
Check solution using 1.25 as 5/4:
{{{(1/5)1.25 + 8 = (-3/5)(1.25-15)}}}
:
.25 + 8 = {{{(-3/5)(-13.75)}}}
8.25 = 8.25 confirms out solution
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