Question 1107919
.
<pre>
sin(t) = {{{-sqrt(1-cos^2(t))}}} = {{{-sqrt(1-(-11/61)^2)}}} = {{{-sqrt(1-121/3721))}}} = {{{-sqrt(3600/3721)}}} = {{{-60/61}}}.


The sign "-" (minus) is taken at sqrt, since the sine function is negative in QIII.


Having cos(t) and sin(t), you can easily calculate all other trigonometric functions, using their definitions.
</pre>