Question 1107907
Assuming the pen has one of its lengths shared be existing pen then;


2B + L = perimeter


2B + L = 150


But L=150-2B or B = 1/2(150-L)


So Area of the pen is;


A = B(150-2B) or 1/2(150L-L^2)


= 150B-2B^2 where L and B are the Length and 


breadth respectively.


Note that Area (A) could also be 1/2(150B-B^2) 

when one of the widths is shared by a pen in 

which case 2L+B=150