Question 1107809
Air-USA has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that only 83% of the booked passengers actually arrive for the flight.) 
Find the probability that if Air-USA books 15 persons, not enough seats will be available. 
prob = (0.83)^15 = 0.0611 
(round to 4 decimal places) 
Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less? 
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no, it is not low enough to not be a concern 
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What about defining unusual as 10% or less? 
yes, it is low enough not to be a concern

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Cheers,
Stan H.
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