Question 1107861
Using 1950 and 2000, 34.7 and 87.3, one has 50 years (x-axis) with a change in per cent of 52.6
This is a slope of 1.052.
Letting 1950=0 and 2000=50, a linear equation with those two data points is
y-y1=m(x-x1) m slope, (x1, y1) a point, and can use (0, 34.7)
y-34.7=1.052*(x)
y=1.052x+34.7, where x is the number of years after 1950.

For 1995, x=45
y=45*1.052+34.7=82.04% or 82.0%