Question 1107663
let w = number of watches.
let p = number of pens.


w + p = 610


1/5 of the watches and 1/3 of the pens were from japan.
a total of 150 watches and pens were from japan.


1/5 * w + 1/3 * p = 150


these 2 equations need to be solved simultaneously.


leave the first equation as is and multiply both sides of the second equation by 5 to get:


w + p = 610
w + 5/3 * p = 750


subtract the first equation from the second to get:


2/3 * p = 140.


solve for p to get 210.



if w + p = 610, and p = 210, then w must be equal to 400.


you get w + p = 400 + 210 = 610.


you get 1/5 * w + 1/3 * p = 1/5 * 400 + 1/3 * 210 = 80 + 70 = 150.


this confirms that the solutions are correct because the original equations are both true when w = 400 and p = 210.


you were asked:


how many watches in the box?
how many pens from Korea? 


since w = the number of watches, then the number of watches in the box = 400.


since p = the number of pens in the box, and since 1/3 of the pens in the box were from japan, then 2/3 of the pens in the box were from korea.


2/3 * p = 2/3 * 210 = 140.


your solution is:


the number of watches in the box was 400.


the number of pens in the box from korea was 140.


if you drew a table of what was in the box, it would look something like this:


<pre>

                       watches             pens           total

japan                    80                 70             150

korea                   320                140             460

total                   400                210             610

</pre>