Question 1107636
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if the difference between the square of a positive integers and the integer before it is 33. what is the integers?
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Here are the two integers before solving:
x and x+1.
Of course, x+1 is an integer, and x is the integer before it.


The description:
{{{x^2-(x+1)=33}}}
{{{x^2-x-1-33=0}}}
{{{x^2-x-34=0}}}
This interpretation is not working.



THE DESCRIPTION ANOTHER WAY:
{{{(x+1)^2-x^2=33}}}
{{{x^2+2x+1-x^2=33}}}
{{{2x+1=33}}}
{{{2x=33-1}}}
{{{2x=32}}}
{{{highlight_green(highlight(x=16))}}}---------


The integers are 16 and 17.




-
check
17^2-16^2=33 ?
{{{289-256}}}
{{{33}}}
{{{yes}}}