Question 1107609
 Solve this system by Substitution.

y = x^2 - 8       and     2x + y =  6
 sol:
y=x^2-8 ---1
2x+y=6 ---2
from 2,
y=6-2x ---3
put 3 in 1
ie, x^2-8=6-2x
x^2+2x-8-6=0
x^2+2x-14=0
then solve the resulting quadratic equation.
GOOD LUCK!