Question 1107493
The cosine function with no phase shift
starting at 0 degrees and going
0, pi/2, pi, 3pi/2, 2pi
max pos, 0, max neg, 0, max pos 
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I get:
{{{ f(t) = 4cos( 2t) -3 }}}
Note that if I say {{{ t = pi }}}, then I get {{{ cos( 2pi ) }}},
which is a complete cycle
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Here is the plot:
{{{ graph( 400,400, -7, 14, -8, 2, 4cos( 2x ) - 3 ) }}}
This looks correct. It has a period of {{{ pi }}}, and the 
max value is {{{ f(t) = 1 }}}, so that is the point ( 0,1 )
That means there is no pase shift.