Question 1107315
Each term before summing is  {{{2+(n-1)*2}}}.


Index of the last term can be found:
{{{2+2(n-1)=102}}}
{{{2+2n-2=102}}}
{{{2n=102}}}
{{{n=51}}}


You want the sum of those fifty-one terms?
Lookup the formula for that.


{{{(2+102)(51/2)}}}--------compute this.