Question 1107305
When the parabola is in the form:
{{{ h(t) = a*t^2 + b*t + c }}} , and also when
{{{ a }}} is negative, as in this case, the formula
for the t-value of the maximum height is:
{{{ t[max] = -b/(2a) }}}
{{{ a = -16 }}}
{{{ b = 54 }}}
{{{ t[max] = -54/( 2*(-16)) }}}
{{{ t[max] = 27/16 }}}
Plug this value for {{{t}}} into the equation
and find {{{ h[max] }}}
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Here is the plot:
{{{ graph( 400,400, -1, 5, -10, 60, -16x^2 + 54x + 7 ) }}}