Question 1107265
(THIS WORK CONTAINS ARITHMETIC MISTAKE)


{{{2x^2+1=h-5x}}}

{{{2x^2+5x+1-h=0}}}


Roots are  p and v.
(BETTER CHOICE MIGHT BE ROOTS ARE p  AND 4p )


{{{p+v=-5/2}}}, and {{{pv=(1-h)/2}}}
(using formulas for sum and product of roots of quadratic equation).


Let v be the larger sized root.
{{{v=4p}}}


Question is, solve for h:
{{{system(p+v=-5/2,2pv=1-h,v=4p)}}}

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{{{cross(h=4)}}}