Question 1107262
Start with the general form of a parabola, {{{y=ax^2+bx+c}}}
(0,0):{{{0=a(0)^2+b(0)+c}}}
1.{{{c=0}}}
.
.
(1,2):{{{2=a(1)^2+b(1)}}}
2.{{{a+b=2}}}
.
.
.
(-1,6): {{{6=a(-1)^2+b(-1)}}}
3.{{{a-b=6}}}
Add 2 and 3,
{{{a+b+a-b=2+6}}}
{{{2a=78}}}
{{{a=4}}}
Now use the equations to solve for b.