Question 1107187
Three consecutive odd integers are such that their sum is more than 57 decreased by twice the greatest of the three integers. What is the smallest integer? 
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1st:: 2x-1
2nd:: 2x+1
3rd:: 2x+3
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Equation::
6x+3 > 57-2(2x+3)
6x+3 > 57-4x-6
10x > 48
x > 4.8
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x = 5
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Answer:: 2x+3 = 2*5+3 = 13
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Cheers,
Stan H.
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