Question 1107203
The general term of Un of a series is defined by the relation Un+1=0.3*(1+Un). n is greater than or equal to 1 and U1 =1. 
Calculate 
U2 = 0.3(1+1) = 0.6
U3 = 0.3(1.6) = 0.48
U4 = 0.3(1.48 = 0.444
----------------------
A second series is defined with the general term Vn, by the relation Vn=Un - 0.5 n is greater than or equal to 1.
Show that this series(Vn) is an exponential series.
V1 = U(1)-0.5
V2 = [U(1)-0.5]2 = 2U(1)-1
V3 = [2U(1)-1]3 = 6U(1)-3
I see no exponentiation.
Cheers,
Stan H.
----------
-------------------
 

Express Vn and hence Un as function of n.