Question 1107022
.
x^3 - 2x^2 - 5x + 6 = x^3 - 3x^2 + x^2 - 5x + 6 = (x^3-3x^2) + (x^2 - 5x + 6) = x^2*(x-3) + (x-2)*(x-3) = (x-3)*(x^2 + (x-2)) = 


= (x-3)*(x^2+x-2) = (x-3)*(x+2)*(x-1).


Solved.