<PRE><B>Question 1106959</B>
TWO DIFFERENT SOLUTIONS OF ALCOHOL WITH RESPECTIVE PROPORTIONS OF WATER TO ALCOHOL OF 3:1 AND 3:2 WERE COMBINED .WHAT IS THE CONCENTRATION OF ALCOHOL IN THE NEW SOLUTION SOLUTION IF THE ORIGINAL SOLUTIONS WERE MIXED IN EQUAL AMOUNT 
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3:1 means 1/4 alcohol or 25% alcohol
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3/2 means 2/5 alcohol or 40% alcohol
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Let &quot;a&quot; be the amt of each liquid.
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Alcohol Eq:: 0.25a + 0.40a = (x/100)(2a)
25a + 40a = x(2a)
65a = 2xa
2x = 65
x = 32.5% alcohol in the new solution
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Cheers,
Stan H.
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