Question 1106921

Let the sides be x, (x+1) and (x+2), where (x+2) is the hypotenuse;


(x+2)^2 = (x+1)^2 + x^2


x^2+4x+4 = x^2+2x+1+x^2


x^2-2x-3=0


(x-3)(x+1)=0


x = 3 since x must be positive


(x+1)=4 and (x+2)=5


Hence the sides are 3, 4 and 5 respectively