Question 1106648
Algebraically determine the domain of y=-2 sqrt x^2-4+1 
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x^2-4x+1 must be >= 0
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If x^2-4x+1 = 0, x = [-4+-sqrt(16-4)]/2 =[-4+-2sqrt(3)]/2 = -2+-sqrt(3)
x is approximately -2+1.73 = 0.27 or x is approximately -3.73
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Ans:: Domain is all x <= -2-sqrt(3) and all x >=-2+sqrt(3)
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Cheers,
Stan H.
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